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a3 + b3 + c3 - 3abc = ( a + b + c).(a2 + b2 + c2 - ab - bc - ca)

Title : a3 + b3 + c3 - 3abc = ( a + b + c).(a2 + b2 + c2 - ab - bc - ca)
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Durasi : 4 minutes
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a3+b3+c3-3abc=(a+b+c)(a2+b2+c2-ab-bc-ca)
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a3 + b3 + c3 - 3abc = ( a + b + c).(a2 + b2 + c2 - ab - bc - ca)
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prove that a³ + b³+ c³ - 3abc = ( a + b + c) ( a² + b² + c ² - ab - bc - ca )
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a3 + b3 + c3 - 3abc = (a + b + c)(a2 + b2 + c2 - ab - bc - ca),
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Prove a3+b3+c3-3abc=(a+b+c)(a2+b2+c2-ab-bc-ac)
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a+b+c = 15 ab+bc+ca = 71 abc = 10 तो a3+b3+c3=
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CLASS 9th | proof of formula a3+b3+c3-3abc=(a+b+c)(a2+b2+c2-ab-bc-ca)
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a³+b³+c³-3abc=(a+b+c)(a²+b²+c²-ab-bc-ca)=1/2(a+b+c){(a-b)²+(b-c)²+(c-a)²]
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